Phylogenetics: BayesTraits Lab
|EEB 349: Phylogenetics|
|In this lab you will learn how to use the program BayesTraits, written by Andrew Meade and Mark Pagel. BayesTraits can perform several analyses related to evaluating evolutionary correlation and ancestral state reconstruction in discrete morphological traits.|
- 1 Download BayesTraits
- 2 Download the tree and data files
- 3 Assessing the strength of association between two binary characters
- 4 Estimating ancestral states
Login to Xanadu and request a machine as usual:
srun --pty -p mcbstudent --qos=mcbstudent bash
Download BayesTraits from Mark Pagel's web site using curl. You can get the tar archive linked to the web site as "BayesTraits V3.0.2 - Linux 64" onto Xanadu however you like, but I think the easiest way is to just use curl:
Now unpack the gzipped "tape archive" as follows:
tar zxvf BayesTraitsV3.0.2-Linux.tar.gz
This will create a directory named BayesTraitsV3.0.2-Linux. The BayesTraitsV3.0.2-Linux folder contains the program itself along with several tree and data files (e.g. Primates.txt and Primates.trees). I will hereafter refer to the folder containing these files as simply the BayesTraits folder. Go back to Mark Pagel's web site and download the manual for BayesTraits. This is a PDF file and should open in your browser window.
A little aside on tar files
Data used to be stored on magnetic tape, not hard drives, and the tar (tape archive) program is what was used to move files to and from the tape. This tells you something about how old the tar format is because perhaps none of you have even seen a magnetic tape used for data storage! The tar command takes all the files in a directory and simply concatenates them into one gigantic file. It also preserves file permissions and the directory structure. The four letters after the command name tar are zxvf. These stand for the following:
- z = uncompress (the gz at the end of the file tells you it is a compressed archive, so the z tells tar to uncompress it before unpacking it)
- x = extract (unpack the archive into individual files. You would use c here if you were creating a tar file)
- v = verbose (tell us what's going on as you unpack)
- f = file (this tells tar that the file name is coming next, so don't put f earlier in the list)
This tar file has been compressed using the program gzip, which adds the gz ending to the file name. Most tar files are compresses with gzip or some similar algorithm so that the file requires less time to move across the internet.
Download the tree and data files
For this exercise, you will use data and trees used in the SIMMAP analyses presented in this paper (you should recognize the names of at least two of the authors of this paper):
Jones C.S., Bakker F.T., Schlichting C.D., Nicotra A.B. 2009. Leaf shape evolution in the South African genus Pelargonium L'Her. (Geraniaceae). Evolution. 63:479–497.
The data and trees were not made available in the online supplementary materials for this paper, but I have obtained permission to use them for this laboratory exercise.
- pelly.txt This is the data file. It contains data for two traits (see below) for 154 taxa in the plant genus Pelargonium.
- pelly.tre This is the tree file. It contains 99 trees sampled from an MCMC analysis of DNA sequences.
You should move these files to a new folder that you create for this lab. For example
cd # cd alone returns you to your home directory mkdir pelly cd pelly curl -O http://hydrodictyon.eeb.uconn.edu/people/plewis/courses/phylogenetics/data/pelly.txt curl -O http://hydrodictyon.eeb.uconn.edu/people/plewis/courses/phylogenetics/data/pelly.tre
Assessing the strength of association between two binary characters
The first thing we will do is see if the two characters (leaf dissection and leaf venation) in pelly.txt are evolutionarily correlated.
Trait 1: Leaf dissection
The leaf dissection trait comprises two states (I've merged some states in the original data matrix to produce just 2 states):
- 0 means leaves are entire (unlobed or shallowly lobed in the original study), and
- 1 means leaves are dissected (lobed, deeply lobed, or dissected in the original study).
Trait 2: Leaf venation
The leaf venation trait comprises two states:
- 0 means leaves are pinnately veined (one main vein runs down the long axis of the leaf blade), and
- 1 means leaves are palmately veined (several major veins meet at the base of the leaf).
To test whether these two traits are correlated, we will estimate the marginal likelihood under two models. The independence model assumes that the two traits are uncorrelated. The dependence model allows the two traits to be correlated in their evolution. The model with the higher marginal likelihood will be the preferred model. You will recall that we discussed both of these models in lecture, and also discussed the stepping-stone method that BayesTraits uses to evaluate models. You may wish to pull up those lectures to help answer the questions that you will encounter momentarily, as well as the BayesTraits manual.
Maximum Likelihood: Independence model
Type the following to start the BayesTraits program (assuming you are in the pelly folder and that the BayesTraitsV3.0.2-Linux is a "sister" folder:
../BayesTraitsV3.0.2-Linux/BayesTraitsV3 pelly.tre pelly.txt
You should see this selection appear:
Please select the model of evolution to use. 1) MultiState 2) Discrete: Independent 3) Discrete: Dependant 4) Continuous: Random Walk (Model A) 5) Continuous: Directional (Model B) 6) Continuous: Regression 7) Independent Contrast 8) Independent Contrast: Correlation 9) Independent Contrast: Regression 10) Discrete: Covarion
Press the 2 key and hit enter to select the Independent model. Now you should see these choices appear:
Please Select the analysis method to use. 1) Maximum Likelihood. 2) MCMC
Press the 1 key and hit enter to select maximum likelihood. Now you should see some output showing the choices you explicitly (or implicitly) made:
Options: Model: Discete Independant Tree File Name: pelly.tre Data File Name: pelly.txt Log File Name: pelly.txt.log.txt Save Initial Trees: False Save Trees: False Summary: False Seed 3162959925 Analsis Type: Maximum Likelihood ML attempt per tree: 10 ML Max Evaluations: 20000 ML Tolerance: 0.000001 ML Algorithm: BOBYQA Rate Range: 0.000000 - 100.000000 Precision: 64 bits Cores: 1 No of Rates: 4 Base frequency (PI's) None Character Symbols: 00,01,10,11 Using a covarion model: False Restrictions: alpha1 None beta1 None alpha2 None beta2 None Tree Information Trees: 99 Taxa: 154 Sites: 1 States: 4
Now type run and hit enter to perform the analysis, which will consist of estimating the parameters of the independent model on each of the 99 trees contained in the pelly.tre file.
Tree No Lh alpha1 beta1 alpha2 beta2 Root - P(0,0) Root - P(0,1) Root - P(1,0) Root - P(1,1) 1 -157.362972 53.767527 34.523176 35.319157 20.707416 0.249998 0.250002 0.249998 0.250002 2 -158.179984 53.313539 34.182683 36.038859 20.997536 0.249999 0.250001 0.249999 0.250001 . . . 98 -156.647307 52.357626 36.749282 27.270771 13.086248 0.250244 0.249756 0.250244 0.249756 99 -156.532925 52.321467 36.641688 27.402067 13.200124 0.250234 0.249767 0.250233 0.249766
You will notice that BayesTraits created a new file: pelly.txt.Log.txt. Rename this file ml-independent.txt so that it will not be overwritten the next time you run BayesTraits:
mv pelly.txt.Log.txt ml-independent.txt
Try to answer these questions using the output you have generated (you'll need to consult the BayesTraits manual, but ask us if anything doesn't make sense):
- Which occurs at a faster rate: pinnate to palmate, or palmate to pinnate?
- Which occurs at a faster rate: entire to dissected, or dissected to entire?
- What do you think Root - P(1,1) means (i.e. the last column of numbers)?
Maximum Likelihood: Dependence model
Run BayesTraits again, this time typing 3 on the first screen to choose the dependence model and again typing 1 on the second screen to select maximum likelihood. You should see this output showing the options selected:
Options: Model: Discete Dependent Tree File Name: pelly.tre Data File Name: pelly.txt Log File Name: pelly.txt.log.txt Summary: False Seed 3601265953 Analsis Type: Maximum Likelihood ML attempt per tree: 10 Precision: 64 bits Cores: 1 No of Rates: 8 Base frequency (PI's) None Character Symbols: 00,01,10,11 Using a covarion model: False Restrictions: q12 None q13 None q21 None q24 None q31 None q34 None q42 None q43 None Tree Information Trees: 99 Taxa: 154 Sites: 1 States: 4
Run the analysis. Here is an example of the output produced after you type run to start the analysis. The column headers don't quite line up with the columns, but you can fix this in a text editor or by copying and pasting the table-like output from the log file into a spreadsheet program:
Tree No Lh q12 q13 q21 q24 q31 q34 q42 q43 Root - P(0,0) Root - P(0,1) Root - P(1,0) Root - P(1,1) 1 -151.930254 66.451053 37.783888 0.000000 62.220033 23.997490 23.299393 46.110432 36.632979 0.24999 0.249981 0.250026 0.250000 2 -152.925691 67.152271 38.611193 0.000000 60.925185 24.514488 23.937433 45.313366 37.199310 0.24999 0.249983 0.250023 0.250001 . . . 98 -150.816306 36.534843 27.359325 0.000000 66.563262 19.823546 24.944519 63.940577 31.074092 0.250048 0.249750 0.250304 0.249898 99 -150.712705 37.316351 27.260833 0.000000 64.364694 20.107653 25.004246 60.945163 31.658536 0.250030 0.249779 0.250272 0.249919
Before doing anything else, rename the file pelly.txt.Log.txt to ml-dependent.txt so that it will not be overwritten the next time you run BayesTraits.
Try to answer these questions using the output you have generated:
- What type of joint evolutionary transitions seem to often have very low rates (look for an abundance of zeros in a column)?
- What type of joint evolutionary transitions seem to often have very high rates (look for columns with rates in the hundreds)?
Bayesian MCMC: Dependence model
Run BayesTraits again, typing 3 on the first screen to choose the dependence model and this time typing 2 on the second screen to select MCMC. You should see this output showing the options selected:
Options: Model: Discete Dependent Tree File Name: pelly.tre Data File Name: pelly.txt Log File Name: pelly.txt.log.txt Summary: False Seed 3792635164 Precision: 64 bits Cores: 1 Analysis Type: MCMC Sample Period: 1000 Iterations: 1010000 Burn in: 10000 MCMC ML Start: False Schedule File: pelly.txt.log.txt.Schedule.txt Rate Dev: AutoTune No of Rates: 8 Base frequency (PI's) None Character Symbols: 00,01,10,11 Using a covarion model: False Restrictions: q12 None q13 None q21 None q24 None q31 None q34 None q42 None q43 None Prior Information: Prior Categories: 100 q12 uniform 0.00 100.00 q13 uniform 0.00 100.00 q21 uniform 0.00 100.00 q24 uniform 0.00 100.00 q31 uniform 0.00 100.00 q34 uniform 0.00 100.00 q42 uniform 0.00 100.00 q43 uniform 0.00 100.00 Tree Information Trees: 99 Taxa: 154 Sites: 1 States: 4
Before typing run type the following command, which tells BayesTraits to change all priors from the default Uniform(0,100) to an Exponential distribution with mean 30:
pa exp 30
- Why am I suggesting this switch?
- Why 30?
Also type the following to ask BayesTraits to perform a stepping-stone analysis:
stones 100 10000
Now run the analysis. This will estimate 100 ratios to brook the gap between posterior and prior, using a sample size of 10000 for each "stone". Here is an example of the output produced after you type run to start the analysis:
Iteration Lh Tree No q12 q13 q21 q24 q31 q34 q42 q43 Root - P(0,0) Root - P(0,1) Root - P(1,0) Root - P(1,1) 11000 -155.195365 78 14.423234 34.800270 8.845985 45.927148 12.622435 50.476188 52.844895 32.149168 0.250068 0.249969 0.249994 0.249968 12000 -154.161705 82 64.601017 12.382781 9.259134 51.796365 12.002095 23.744903 30.316089 21.865930 0.249936 0.249957 0.250095 0.250012 . . . 1009000 -154.343996 30 33.555198 50.086092 11.294490 38.518607 24.461032 47.295157 43.477964 21.726938 0.250057 0.249939 0.250045 0.249959 1010000 -154.195259 87 29.584898 35.410909 2.003582 61.981073 16.976124 14.895266 49.111354 14.419644 0.251115 0.247854 0.252551 0.248480
Before doing anything else, rename the file pelly.txt.Log.txt to mcmc-dependent.txt, and pelly.txt.log.Stones.txt to mcmc-dependent.Stones.txt so that they will not be overwritten the next time you run BayesTraits.
You will notice a column not present in the likelihood analysis named Tree No that shows which of the 99 trees in the supplied pelly.tre treefile was chosen at random to be used for that particular sample point. BayesTraits is sampling trees from the posterior distribution here; it cannot actually sample trees from the posterior because we have given it only data for two morphological characters, which would not provide nearly enough information to estimate the phylogeny for 154 taxa. It is as if we had given BayesTraits sequence data as well as our 2 morphological characters and it was using only the sequence data to estimate the posterior distribution of trees and edge lengths and only the morphological data to estimate rates for the morphological characters.
Try to answer these questions using the output you have generated:
- What is the log marginal likelihood estimated using the stepping-stone method? This value is listed on the last line of the file mcmc-dependent.Stones.txt (your value may differ from mine slightly)
Bayesian MCMC: Independence model
Run BayesTraits again, this time specifying the Independent model, and again using MCMC, pa exp 30, and stones 100 10000. Rename the output file from pelly.txt.log.txt to mcmc-independent.txt. Also rename pelly.txt.log.Stones.txt to mcmc-independent.Stones.txt.
- What is the estimated log marginal likelihood for this analysis using the stepping-stone method?
- Which is the better model (dependent or independent) according to these estimates of marginal likelihood?
Bayesian Reversible-jump MCMC
Run BayesTraits again, specifying Dependent model, MCMC and, this time, specify the reversible-jump approach using the command
rj exp 30
The previous command also sets the prior. Type run to start, then when it finishes rename the output file rjmcmc-dependent.txt.
The reversible-jump approach carries out an MCMC analysis in which the number of model parameters (the dimension of the model) potentially changes from one iteration to the next. The full model allows each of the 8 rate parameters to be estimated separately, while other models restrict the values of some rate parameters to equal the values of other rate parameters. The output contains a column titled Model string that summarizes the model in a string of 8 symbols corresponding to the 8 rate parameters q12, q13, q21, q24, q31, q34, q42, and q43. For example, the model string "'1 0 Z 0 1 1 0 2" sets q21 to zero (Z), q13=q24=q42 (parameter group 0), q12=q31=q34 (parameter group 1), and q43 has its own non-zero value distinct from parameter groups 0 and 1.
You could copy the "spreadsheet" part of the output file into Excel and sort by the model string column, but let's instead use Python to summarize the output file. Download (e.g. using curl) the file btsummary.py file and run it as follows:
This should produce counts of model strings. (If it doesn't, check to make sure your output file is named rjmcmc-dependent.txt because btsummary.py tries to open a file by that name.) Answer the following questions using the counts provided by btsummary.py.
- Which model string is most common?
- What does this model imply?
Notice that many (but not all) model strings have Z for q21. One way to estimate the marginal posterior probability of the hypothesis that q21=0 is to sum the counts for all model strings that have Z in that third position corresponding to q21. It is easy to modify btsummary.py to do this for us: open btsummary.py and locate the line containing the regular expression search that pulls out all the model strings from the BayesTrait output file:
model_list = re.findall("'[Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9]", stuff, re.M | re.S)
The re.findall function performs a regular expression search of the text stored in the variable stuff looking for strings that have a series of 8 space-separated characters, each of which is either the character Z or a digit between 0 and 9 (inclusive). Copy this line, then comment out one copy by starting the line with the hash (#) character:
#model_list = re.findall("'[Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9]", stuff, re.M | re.S) model_list = re.findall("'[Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9] [Z0-9]", stuff, re.M | re.S)
Now modify the copy such that it counts only models with Z in the third position of the model string. Rerun btsummary.py, and now the total matches should equal the number of model strings sampled in which q21=0.
- So what is the estimated marginal posterior probability that q21=0?
- Why is the term marginal appropriate here (as in marginal posterior probability)?
Estimating ancestral states
Start BayesTraits in the usual way, specifying 1 (Multistate) on the first screen and 2 (MCMC) on the second. After the options are output, type the following commands in, one line at a time, finishing with the run command:
pa exp 30 addtag xero alternans104 rapaceum130 addmrca xero xero run
The addmrca command tells BayesTraits to add columns of numbers to the output that display the probabilities of each state for each character in the most recent common ancestor of the taxa listed in the addtag command (2 taxa are sufficient to define the MRCA, but more taxa may be included). The column headers for the last four columns of output should be (I've added the comments starting with <--)
xero - S(0) - P(0) <-- character 0 (dissection), probability of state 0 (unlobed) xero - S(0) - P(1) <-- character 0 (dissection), probability of state 1 (dissected) xero - S(1) - P(0) <-- character 1 (venation), probability of state 0 (pinnate) xero - S(1) - P(1) <-- character 1 (venation), probability of state 1 (palmate)
- Which state is most common at the xerophyte MRCA node for leaf venation?
- Which state is most common at the xerophyte MRCA node for leaf dissection?
That concludes the introduction to BayesTraits. A glance through the manual will convince you that there is much more to this program than we have time to cover in a single lab period, but you should know enough now to explore the rest on your own if you need these features.